{-# OPTIONS --cubical-compatible #-}
module Padova2025-zh-TW.ComputationalContent.Fictions.InfinitelyMany (⊥ : Set) where
無窮子序列#
open import Padova2025-zh-TW.ProgrammingBasics.Booleans
open import Padova2025-zh-TW.ProgrammingBasics.Naturals.Base
open import Padova2025-zh-TW.ProgrammingBasics.Naturals.Arithmetic
open import Padova2025-zh-TW.ProvingBasics.Equality.Base
open import Padova2025-zh-TW.ProvingBasics.Connectives.Disjunction
open import Padova2025-zh-TW.ProvingBasics.Connectives.Existential
open import Padova2025-zh-TW.ProvingBasics.Connectives.Conjunction
open import Padova2025-zh-TW.ProvingBasics.Termination.Ordering
open import Padova2025-zh-TW.ComputationalContent.DoubleNegation (⊥)
習題 1
not-true-is-falsenot-true-is-false : {x : Bool} → ¬ (true ≡ x) → ¬ ¬ (false ≡ x)
not-true-is-false = {!!}
你的解答
條件 Boundedly α P 表示謂詞 P 只被 α 的有限多個值所滿足。
Boundedly : {X : Set} → (ℕ → X) → (X → Set) → Set
Boundedly f P = Σ[ a ∈ ℕ ] ((b : ℕ) → b ≥ a → ¬ P (f b))
條件 Infinitely α P 以正面的方式表示,α 的值有無限多次滿足 P。
Infinitely : {X : Set} → (ℕ → X) → (X → Set) → Set
Infinitely f P = (a : ℕ) → ¬ ¬ (Σ[ b ∈ ℕ ] b ≥ a × P (f b))
習題 2
lemmalemma : {X : Set} → {α : ℕ → X} {P : X → Set} → ¬ Boundedly α P → Infinitely α P
lemma {α = α} {P = P} p a = oracle {∃[ b ] b ≥ a × P (α b)} ⟫= λ
{ (left q) → {!!}
; (right q) → {!!}
}
你的解答
InfinitaryPigeonholePrinciple : (ℕ → Bool) → Set
InfinitaryPigeonholePrinciple α = Infinitely α (false ≡_) ⊎ Infinitely α (true ≡_)
習題 3
infinitary-pigeonhole-principleinfinitary-pigeonhole-principle : (α : ℕ → Bool) → ¬ ¬ InfinitaryPigeonholePrinciple α
infinitary-pigeonhole-principle α = oracle {Boundedly α (true ≡_)} ⟫= λ
{ (left (a , p)) → {!!}
; (right p) → {!!}
}
你的解答
參考解答
infinitary-pigeonhole-principle : (α : ℕ → Bool) → ¬ ¬ InfinitaryPigeonholePrinciple α
infinitary-pigeonhole-principle α = oracle {Boundedly α (true ≡_)} ⟫= λ
{ (left (a , p)) → return (left λ i →
not-true-is-false (p (max i a) (max-inflationaryᵣ i a)) ⟫= λ q →
return (max i a , max-inflationaryₗ i a , q))
; (right p) → return (right (lemma {P = (true ≡_)} p))
}